An Executive Of Trident Communications Recently Traveled To London, P…

An executive of Trident Communications recently traveled to London, Paris, and Rome. He paid $180, $230, and $160 per night for lodging in London, Paris, and Rome, respectively, and his hotel bills totaled $2660. He spent $110, $120, and $90 per day for his meals in London, Paris, and Rome, respectively, and his expenses for meals totaled $1520 If he spent as many days in London as he did in Paris and Rome combined, how many days did he stay in each city? ​

Answer:

The executive stayed in London for 2 days and in Paris and Rome for 5 days each.

Step-by-step explanation:

Let’s assume that the executive stayed in London for ‘x’ days.

Since he spent as many days in London as he did in Paris and Rome combined, the total number of days he stayed in Paris and Rome can be represented as (x + x) = 2x.

The total cost of lodging in London, Paris, and Rome is given as $2660. We can set up the following equation:

($180 * x) + ($230 * (2x)) + ($160 * (2x)) = $2660

Simplifying the equation:

180x + 230(2x) + 160(2x) = 2660

180x + 460x + 320x = 2660

960x = 2660

x = 2660 / 960

x ≈ 2.77

Since we cannot have fractional days, we’ll round down to the nearest whole number. Thus, the executive stayed in London for 2 days.

Now, let’s calculate the number of days he stayed in Paris and Rome:

Number of days in Paris and Rome = 2x = 2 * 2.77 ≈ 5.54

Again, rounding down to the nearest whole number, the executive stayed in Paris and Rome for 5 days each.

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An Executive Of Trident Communications Recently Traveled To London, P…

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